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0=-5x^2+10x-15
We move all terms to the left:
0-(-5x^2+10x-15)=0
We add all the numbers together, and all the variables
-(-5x^2+10x-15)=0
We get rid of parentheses
5x^2-10x+15=0
a = 5; b = -10; c = +15;
Δ = b2-4ac
Δ = -102-4·5·15
Δ = -200
Delta is less than zero, so there is no solution for the equation
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